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Find two solutions for each of the following equations:(i) `4x+3y=12` (ii) `2x+5y=0` (iii) `3y+4=0`

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To find two solutions for each of the given equations, we will substitute different values for \(x\) or \(y\) and solve for the other variable. Let's go through each equation step by step. ### (i) Equation: \(4x + 3y = 12\) **Step 1:** Let \(x = 0\). Substituting \(x = 0\) into the equation: \[ 4(0) + 3y = 12 \implies 3y = 12 \implies y = \frac{12}{3} = 4 ...
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