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The Speed Of a particle moving in a plan...

The Speed Of a particle moving in a plane is equal to the magnitude of its instantaneous velocity, `v=|vl= sqrt(v_x^2+v_y^2).`
(a) Show that the rate of change of the speed is `(dv)/(dt)=(v_xa_x+v_ya_y)/(sqrt(v_x^2+v_y^2))`.
(b) Show that the rate of change of speed can be expressed as `(dv)/(dt)` is equal to`a_t` the component of a that is parallelto v.

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