If `tanA-tan B=x`, and `cot B-cotA=y`, then find the value of `cot(A-B)`.

If tan A-tan B=x and cot B-cot A=y, then cot (A-B)=

If tanA-tanB=x and cotB-cotA=y , then cot(A-B)=?

If (tanA-tanB)=x and (cotB-cotA)=y ,then cot(A-B)

If tan A - tan B =x and cot B - cot A=y, then: cot(A-B)=

If tan A - tan B = x and cot B - cot A= y, then cot (A-B) is

If tan A - tan B = x and cot B - cot A =y , then what is cot ( A -B) equal to ?

If tan A - tan B = x and cot B - cot A =y , then what is cot ( A -B) equal to ?.............. A) 1/x +ya B) (1)/(xy) C) (1)/(x) -(1)/(y) D) (1)/(x) +1/y

If tan A -tan B = x and cot B - cot A = y, prove that cot(A-B)=1/x+1/y

If tan A - tan B = x and cot A - cot B = y, then cot( A- B) =