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If F:[1,x)->[2,x] is given by f(x)=x+1/x...

If `F:[1,x)->[2,x]` is given by `f(x)=x+1/x,` then `f^-1 (x)` equals. (a) `(x+sqrt(x^2-4))/2` (b) `x/(1+x^2)` (c) `(x-sqrt(x^2-4))/2` (d) `1+sqrt(x^2-4)`

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