`sin(n+1)Asin(n-1)A+cos(n+1)Acos(n-1)A=cos2A`

Prove that: sin(n+1)A sin(n+2)A+cos(n+1)A cos(n+2)A=cos A

Prove that: sin(n+1)As in(n+2)A+cos(+1)A cos(n+2)A=cos A

sin(n+1)xsin(n+2)x+cos(n+1)xcos(n+2)x=cosx

sin(n+1)xsin(n+2)x+cos(n+1)xcos(n+2)x=cosx

Select the correct options from the given alternatives.The value of sin(n+1)Asin(n+2)A+cos(n+1)Acos(n+2)A is equal to….

sin (n + 1) A * sin (n-1) A + cos (n + 1) A * cos (n-1) A = cos2A

Prove that sin(n+1)xsin(n+2)x+cos(n+1)xcos(n+2)x=cosx

Prove that sin(n+1)xsin(n+2)x+cos(n+1)xcos(n+2)x=cosx

Prove the following: sin[(n+1)A].sin[(n+2)A]+cos[(n+1)A].cos[(n+2)A]=cosA