Let `y = f(x)` be a differentiable function such that `f(-1) = 2, f(2) =-1` and `f(5) =3` then the equation `f'(x) = 2 f(x)` has

Let y=f(x) be a differentiable function such that f(−1)=2,f(2)=−1 and f(5)=3 If the equation f (x)=2f(x) has real root. Then find f(x)

If f(x) be a differentiable function such that f(x+y)=f(x)+f(y) and f(1)=2 then f'(2) is equal to

If f(x) is a twice differentiable function and given that f(1)=2,f(2)=5 and f(3)=10 then

If f(x) is a twice differentiable function and given that f(1)=2,f(2)=5 and f(3)=10 then

Let f:(0,oo)->R be a differentiable function such that f'(x)=2-f(x)/x for all x in (0,oo) and f(1) =1 , then

Let f:(0,oo)->R be a differentiable function such that f'(x)=2-f(x)/x for all x in (0,oo) and f(1)=1 , then

Let f:(0,oo)->R be a differentiable function such that f'(x)=2-f(x)/x for all x in (0,oo) and f(1)=1 , then

If f(x) be a differentiable function,such that f(x)f(y)+2=f(x)+f(y)+f(xy);f'(0)=0,f'(1)=2 then find f(x)

Let f : R to R be a differentiable function such that f(2) = -40 ,f^1(2) =- 5 then lim_(x to 0)((f(2 - x^2))/(f(2)))^(4/(x^2)) is equal to