If the rank of the matrix [(lambda,-1,0),(0, lambda,-1),(-1,0,lambda)] is 2, then find lambda .

For a non zero " lambda" ,the value of matrix "[[lambda,1,0],[0,lambda,1],[0,0,lambda]]^(n) " is equal to

If A= [[2,3,5],[1,2,1],[0,1,7]] and A^(3)-lambda A^(2)+28A-10=0 , then the value of lambda is

If A = [{:(lambda,1),(-1,-lambda):}] , then for what values of lambda, A^(2) =0 ? …………..

[" 2.Let matrix "A=[[1,y,4],[2,2,z]]" ; if "xyz=2 lambda" and "8x+4y+3z=lambda+28," then "(adj A)" A equals: "],[[" (A) "[[lambda+1,0,0],[0,lambda+1,0],[0,0,lambda+1]]," (B) "[[lambda,0,0],[0,lambda,0],[0,0,lambda]]],[" (C) "[[lambda^(2),0,0],[0,lambda^(2),0],[0,0,lambda^(2)]]," (D) "[[lambda+2,0,0],[0,lambda+2,0],[0,0,lambda+2]]]]

If A=[[3 ,1],[-1 ,2]] and I=[[1, 0],[ 0, 1]] , then find lambda so that A^2=5A+lambdaI

Number of real values of lambda for which the matrix A=[[2,-1,32,-1,3lambda+3,lambda-2,lambda+7]] has no inverse (A) 0(B)1(C)2(D) infinite ]]

If the following equations x+y-3=0,(1+lambda)x+(2+lambda)y-8=0,x-(1+lambda)y+(2+lambda)=0 are consistent then the value of lambda is