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Mean deviation for n observation x(1),x(...

Mean deviation for n observation `x_(1),x_(2),…..x_(n)` from their mean `bar x` is given by

A

`overset(n)underset(i=1)Sigma(x_(i)-barx)`

B

`(1)/(n)overset(n)underset(i=1)Sigmaabs(x_(i)-barx)`

C

`overset(n)underset(i=1)Sigma(x_(i)-barx)^(2)`

D

`(1)/(n)overset(n)underset(i=1)Sigma(x_(i)-barx)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(1)/(n)overset(n)underset(i=1)Sigmaabs(x_(i)-barx)`
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