If `|[4-x, 4+x, 4+x], [4+x, 4-x, 4+x],[4+x, 4+x, 4-x]| = 0` find the value of x.

Answer

N/a

Explanation

Given `|(4-x,4+x,4+x),(4+x,4-x,4+x),(4+x,4+x,4-x)|=0`
`implies |(12+x,12+x,12+x),(4+x,4-x,4+x),(4+x,4+x,4-x)|=0 [ :.R_(1)toR_(1)+R_(2)+R_(3)]`
`implies (12+x)|(1,1,1),(4+x,4-x,4+x),(4+x,4+x,4-x)|=0` [taking `(12+x)` common from `R_(1)`]
`(12+x)|(0,0,1),(0,8,4+x),(2x,8,4-x)|=0 [ :' C_(1)toC_(1)-C_(3)` and `C_(2)toC_(2)+C_(3)]`
`implies(12+x)[1.(-16x)]=0`
`implies (12+x)(-16x)=0`
`:. (12+x)(-16x)=0`
`=x=-12,0`