If `cos2theta=0`, then `|(0,costheta,sin theta),(cos theta, sin theta, 0),(sin theta, 0, cos theta)|^(2)` is equal to…………

Answer

N/a

Explanation

Sicne `cos2 theta=0`
`implies cos 2theta= "cos" (pi)/2implies2 theta=(pi)/2`
`implies theta=(pi)/4`
`:. "sin" (pi)/4=1/(sqrt(2))` and `"cos"(pi)/4=1/(sqrt(2))`
`:. |(0,1/(sqrt(2)),1/(sqrt(2))),(1/(sqrt(2)),1/(sqrt(2)),0),(1/(sqrt(2)),0,1/(sqrt(2)))|`
Expanding along `R_(1)`
`=[-1/(sqrt(2))(1/2)+1/(sqrt(2))(-1/2)]^(2)=[(-2)/(2sqrt(2))]^(2)=((-1)/(sqrt(2)))^(2)=1/2`