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"S o l v e"int0^(pi/2)(cosx)/((1+sinx)(2...

`"S o l v e"int_0^(pi/2)(cosx)/((1+sinx)(2+sinx))dx`

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int_0^(pi/2) cosx/(1+sinx)dx

int_0^(pi/2) cosx/(1+sinx)dx

Find int_0^(pi/2) cosx/((1+sinx)(2+sinx))dx

int_(0)^( pi/2)(cosx)/(1+sinx)dx

int_(0)^(pi)(cosx)/(1+sinx)dx=

int_(0)^(pi//2)(cosx)/(1+sinx)dx=

int_0^(pi/2) (cos x)/(sinx + cosx) dx =

int_0^(pi/2) (cosx-sinx)/(1+sinx cosx) dx =