If `alpha+beta=theta` and `tanalpha:tanbeta=x:y`, prove that `sin(alpha-beta)=(x-y)/(x+y)sintheta`.

If alpha+beta=theta and tan alpha:tan beta=x:y, prove that sin(alpha-beta)=(x-y)/(x+y)sin theta

If alpha+beta=theta and (tan alpha)/(tan beta)=(x)/(y), prove that sin(alpha-beta)=(x-y)/(x+y)sin theta

If alpha+beta=theta and (tan alpha)/(tan beta) = x/y , prove that sin (alpha-beta) = (x-y)/(x+y) sin theta

An angle theta is divided into two parts alpha, beta such that tan alpha: tan beta = x:y prove that sin (alpha-beta)=frac{x-y}{x+y}sin theta

An angle theta is divided into two parts alpha " and " beta such that tan alpha : tan beta = x : y : " prove that ", sin (alpha - beta) =(x-y)/(x+y) sin theta.

if tanalpha -tanbeta =x and cotbeta-cotalpha =y prove that cot(alpha-beta) = (x+y)/(xy)

if tan alpha-tan beta=x and cot beta-cot alpha=y prove that cot(alpha-beta)=(x+y)/(xy)

If 2tanalpha=3 tanbeta , show that tan(alpha-beta)=(sin2beta)/(5-cos2beta)

If alphaandbeta are such that tanalpha=2tanbeta , then what is sin(alpha+beta) equal to ?

If tan theta = (x sin alpha + y sin beta)/(x cos alpha + y cos beta), "prove that " x sin (theta - alpha) + y sin (theta - beta) = 0