The change in oxidation number of "S" ,in the reaction of \(I_{2}\) with \(Na_{2}S_{2}O_{3}\) is

The oxidation number of S in Na_(2)S_(2) is

When \(Cl_{2}\) is treated with \(Na_{2}S_{2}O_{3}\) the oxidation state of sulphur in the product is x .When \(I_{2}\) is treated with \(Na_{2}S_{2}O_{3}\) the oxidation state of sulphur in the product is y. What is [x+2y/11]

The oxidation number of S in Na_(2)S_(4)O_(6) is

Oxidation number of S in S_(2)O_(2)^(-2) is

Oxidation number of S in Na_(2)S_(4)O_(6) is

The equivalent weight of hypo in the reaction (M=M" .Wt) \(2Na_{2}S_{2}O_{3}+I_{2} \rightarrow 2NaI+Na_{2}S_{4}O_{6}\) is

The oxidation number of sulphur in Na_2S_4O_6 is .