In a double slit experiment, at a certain point on the screen the path difference between the two interfering waves is `1/3 rd` of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is:

At a certain point on a screen the path difference for the two interfering rays is (1//8)^(th) of a wavelength. Find the ratio of the intensity at this point to that at the centre of a bright fringe

In a Young's double slit experiment , the path difference at a certain point on the screen ,between two interfering waves is 1/8 th of wavelength.The ratio of the intensity at this point to that at the center of a bright fringe is close to :

The path of difference between two interfering waves at a point on the screen is (lambda)/(8) . The ratio of intensity at this point and that at the central fringe will be :

The path difference between two interfering waves of equal intensities at a point on the screen is lambda//4 . The ratio of intensity at this point and that at the central fringe will be

If the path difference between the interfering waves is n lambda , then the fringes obtained on the screen will be

The path difference between two interfering waves at a point on screen is 70.5 tomes the wave length. The point is

In Young's double-slit experiment, the path difference between two interfering waves at a point on the screen is 13.5 times the wavelength. The point is

If path difference between two interfering waves arriving at a point is zero, then the point will

In Young’s double slit experiment, light from two identical sources are superimposing on a screen. The path difference between the two lights reaching at a point on the screen is frac{7 lambda}{4} . The ratio of intensity of fringe at this point with respect to the maximum intensity of the fringe is :