A particle has same range for two angle of projection with same speed `10ms^(-1)` .The corresponding maximum height attained by particle is `H_(1)` and `H_(2)` respectively.Then, `H_(1)+H_(2)` is? `(g=10m/s^(2))`

A projectil has the same range (R ) when the maximum heitht attained by it is either H_1 or H_1 . Find the relation between R, H_1 and H_2 .

A particle is projected radially outwards from the surface of a planet with an initial speed of 4.0km//s . Maximum height attained by the particle is h=900km . Find the radius of the planet taking g=10m//s^(2) .

A body is projected from the ground with a velocity v = (3hati +10 hatj)ms^(-1) . The maximum height attained and the range of the body respectively are (given g = 10 ms^(-2))

A projectile has the same range R for two angles of projections but same speed. If T_(1) and T_(2) be the times of flight in the two cases, then Here theta is the angle of projection corresponding to T_(1) .

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

Two particles are projected obliquely from ground with same speed such that their range 'R' are same but they attain different maximum heights h_(1) and h_(2) then relation between R, h_(1) and h_(2) is:

Two stones are thrown with same speed u at different angles from ground n air if both stones have same range and height attained by them are h_(1) and h_(2) , then h_(1) + h_(2) is equal to

Three projecties are thrown all with same speed u but at different angles of projection (thetagttheta_(2)gttheta_(3)) all taken from horizontal. Maximum height attained by projectile (3) is H . Range of (1) & (3) is same & that of (2) is maximum for the given speed. At height H , speeds are v_(1),v_(2)&v_(3) as shown. Total time of flights are T_(1),T_(2)&T_(3) . Choose the correct statement(s).