The angle of elevation of the top of a T.V. tower from three points A,B,C in a straight line in the horizontal plane through the foot of the tower are `alpha, 2alpha, 3alpha` respectively. If AB=a, the height of the tower is

The angles of elevation of the top of a TV tower from three points A,B and C in a straight line (in thehorizontal plane) through the foot of tower are alpha,2 alpha and 3 alpha respectively.If AB=a, the height of tower is

The angle of elevation of the top of a tower from two points A and B lying on the horizontal through the foot of the tower are respectively 15^(@)and30^(@) .If A and B are on the same side of the tower and AB = 48 metre , then the height of the tower is :

The angle of elevation of the top of a tower from a point 40 m away from its foot is 60^(@) . Find the height of the tower.

The angle of elevation of the top of a tower standing on a horizontal plane from two points on a line passing through the foot of the tower at a distance x and y respectively are complementary angles. Find the height of the tower.

The angle of elevation of the top of a tower standing on a horizontal plane from two on a line passing through the foot of the tower at a distance 9 ft and 16 ft respectively are complementary angles. Then the height of the tower is:

If the angles of elevation of the top of tower from three collinear points A , B and C , on a line leading to the foot of the tower, are 30^(@) , 45^(@) and 60^(@) respectively, then the ratio , AB : BC is

The angle of elevation of the top of a tower standing on a horizontal plane from two points on a line passing through the foot of the tower at a distance 9 ft and 16 ft. respectively are complementary angles. The height of the tower is