The tangent at `P` on the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` cuts the major axis in `T` and `PN` is the perpendicular to the `x` -axis, `C` being centre then `CN.CT`

The tangent at point P on the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 cuts the minor axis in Q and PR is drawn perpendicular to the minor axis. If C is the centre of the ellipse, then CQ*CR =

For the ellipse ((x+y-1)^(2))/(9)+((x-y+2)^(2))/(4)=1 the end of major axis are

If the normal at P(theta) on the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 with focus S ,meets the major axis in G. then SG=

P is a variable on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 with AA' as the major axis.Find the maximum area of triangle APA'

Equation of major axis of the ellipse ((x-h)^(2))/(a^(2))+((y-k)^(2))/(b^(2))=1 (a

Length of the focal chord of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 which is inclined to the major axis at angle theta is

Ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a>b) Equation of the circle described on major axis as diameter is

Extrremities of the latera recta of the ellipses (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a>b) having a given major axis 2a lies on

If normal to x^(2)/a^(2)+y^(2)/b^(2)=1 at any point P meets the major axis is G and PN is perpendicular to the major axis then (CG)/(CN) = (where C is the centre of the ellipse) "