The equation of director circle of `(x-x_(1))^(2)+(y-y_(1))^(2)=r^(2)` is

The equation to the director circle of (x^(2))/(6)+(y^(2))/(4)=1 is

The Equation of director circle of x^(2)+y^(2)+6x+2y+1=0 is

The equation of director circle to the circle x^(2) + y^(2) = 8 is

Equation of director circle of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

The equation of the director circle of the hyperbola (x^2)/(16)-(y^2)/(4) = 1 is given by :

Find the equation of a circle, the co-ordinates of the ends of whose diameter are (-1,-3) and (2,5) Now the equation of circle (x-x_(1))(x-x_(2))+(y-y_(1))(y-y_(2))=0 rArr(x+1)(x-2)+(y+3)(y-5)=0 rArr x^(2)-x-2+ y^(2)-2y-15=0 rArr x^(2)+y^(2)-x-2y-17=0 We is the required equation.

If radii of director circles of (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 are 2r and r respectively,let e_(E) and e_(H) are the eccentricities of ellipse and hyperbola respectively,then

Let complex numbers alpha and (1)/(alpha) lies on circle (x-x_(0))^(2)(y-y_(0))^(2)=r^(2) and (x-x_(0))^(2)+(y-y_(0))^(2)=4r^(2) respectively.If z_(0)=x_(0)+iy_(0) satisfies the equation 2|z_(0)|^(2)=r^(2)+2 then | alpha| is equal to (a) (1)/(sqrt(2))( b )(1)/(2)(c)(1)/(sqrt(7)) (d) (1)/(3)

If the end points of a diameter of circle are A(x_(1),y_(1)) and B(x_(2),y_(2)) then show that equation of circle will be (x-x_(1))(x-x_(2))+(y-y_(1))(y-y_(2))=0