`5y^2 -10y-4x+1=0` is a conic. Find the length of latus rectum of conic and the least distance between the conic and its director circle.

The length of the latus rectum of a conic is 5. Its focus is (-1,1) and its directrix is 3x-4y+2=0, then the conic is

Two parabolas have coordinate axes as their directrices and having same focus.If the square of latus rectum of one parabola is equal to length of latus rectum of second and locus of focus is conic C, then length of latus rectum of conic C is

Consider the conic find 9y^2-4x^2=36 Length of latus rectum.

Find the foci of the conic y^(2)+2x+2y=5 .

The latus rectum of a conic section is the width of the function through the focus.the possitive difference between the length of the latus rectum of 3y=x^(2)+4x-9andx^(2)+4y^(2)-6x+16y=24 is- -

The eccentricity of a conic is the difference between the roots of x^(2)-5x+4=0 .Then the conic is

A conic has latus rectum length 1, focus at (2,3) and the corresponding directrix is x+y -3=0 . Then the conic is

The ends of the latus rectum of the conic x^(2) + 10x -16y + 25 = 0 are...

The eccentricity of the conic 4x^2-9y^2=2 is :