Each diagonal of a ||gm divides it into two triangles of the same area

Asserion (A) : The diagonals of a ||gm divide it into four triangle of equal area. Reason (R ) : A diagonal of a ||gm divides it into two triangle of equal area.

A diagonal of a parallelogram divides it into two triangles of equal area.

A diagonal of a parallelogram divides it into two triangles of equal area. GIVEN : A parallelogram A B C D in which B D is one of the diagonals. TO PROVE : ar ( A B D)=a r( C D B)

Show that a median of a triangle divides it into two triangles of equal area.

Show that a median of a triangle divides it into two triangles of equal areas.

Median divides a triangle into two triangles of the same area

If A(4,-6),B(3,-2) and C(5,2) are the vertices of $ABC, then verify the fact that a median of a triangle ABC divides it into two triangles of equal areas.

Assertion (A) : If ABCD is a rhombus whose one angle is 60^(@) then the ratio of the lengths of its diagonals is sqrt3 : 1 Reason (R ) : Median of a triangle divides it into two triangle of equal area.

The median of a triangle divides it into two

Show that the diagonals of a parallelogram divide it into four triangles of equal area.