Area of trapezium

The area of a trapezium is half the product of its height and sum of parallel sides.

The area of a trapezium is 105 sq. m and the lengths of its parallel sides are 9 m and 12 m respectively then the height of the trapezium is :

The area of a trapezium is 105 meter^2 and the lengts of its parallel sides are 9 m and 12 m respectively . Then the height of the trapezium is

(i) Area of triangle = (1)/(2)xx(…..)xx(…..) . (ii) Area of a||gm=(1)/(2)xx(……)xx(……) . (iii) Area of a trapezium =(1)/(2)xx(……)xx(……) . (iv) The parallel sides of a trapezium are 14 cm and 18 cm and the distance between them is 8 cm. The area of the trapezium is ……. cm^(2) .

The area of a trapezium is defined by function ? and given by f(x) =(10+x) sqrt(100-x^(2)) , then the area when it is maximised is:

The area of a trapezium is 126 sq .cm .the height of the trapezium is 7 cm .If one of the bases is longer than the other by 6cm , find the lengths of the bases .

Area and Perimeter of trapezium

The difference between two parallel sides of a trapezium is 8 cm. The perpendicular distance between them is 19 cm while the area of trapezium is 760 sq cm. What will be the lengths of the parallel sides?

Two parallelogram sides of a trapezium are 12 cm and 8 cm long and the distance between them is 6.5 cm. The area of the trapezium is