In an isosceles triangle ABC with `AB= AC, BD` is perpendicular from B to the side AC. Prove `BD^2-CD^2 = 2CD. AD`.

In an isosceles triangle ABC with AB=ACBD is perpendicular from B to the side AC. Prove that BD^(2)-CD^(2)=2CDAD

In an isosceles triangle ABC with AB = AC, BD is perpendicular from B to side AC. Prove that BD^(2)-CD^(2)=2CD.AD

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

DeltaABC is an isosceles triangle. AB = AC and BD is perpendicular on AC from vertex B, then BD^(2)-CD^(2) is equal to-

In an isosceles triangle ABC, AB = AC and D is a point on BC produced. Prove that : AD^(2)=AC^(2)+BD.CD

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: BD = CD

ABC is an isosceles triangle with AB = AC and D is a point on AC such that BC^2=ACxxCD . Prove that BD = BC

ABC is an isosceles triangle with AB=AC and D is a pooint on AC such that BC^(2)=ACxCD .Prove that BD=BC