if `f(t) =t^3+sqrt2t^2+3(sqrt2t)-1`, then evaluate `f(2sqrt2)`

int dt/sqrt[3t-2t^2]

If int_(sinx)^1 t^2f(t)dt=1-sinx , then the value of f(1/sqrt(3)) is (A) 1/sqrt(3) (B) 1/3 (C) sqrt(3) (D) 3

int(dt)/(sqrt(3t-2t^2))

If int_(sin x)^(1) t^2 f(t) dt = 1 - sin x , then the value of f(1/(sqrt3)) is :

If int_(sinx)^(1) t^(2) f(t) dt =1-sinx , then the value of f((1)/(sqrt(3))) is -

If x = sqrt((1 - t^2)/(1 + t^2)), y = (sqrt(1 + t^2) - sqrt(1 - t^2))/(sqrt(1 + t^2) + sqrt(1 -t^2)) then (dy)/(dx) =

If y=tan^(-1) [(sqrt(1+t^(2))+sqrt(1-t^(2)))/(sqrt(1+t^(2))-sqrt(1-t^(2)))] , find the value of (dy)/(dt) .

int frac{ t^2 + 1}{ t^4 + 1} dt=...........a) frac{1}{sqrt2}[tan^(-1)(sqrt 2t-1)+tan^(-1)(sqrt 2t+1)]+c b) sqrt2[tan^(-1)(sqrt 2t-1)+tan^(-1)(sqrt 2t+1)]+c c) frac{1}{2sqrt2}[tan^(-1)(sqrt 2t-1)+tan^(-1)(sqrt 2t+1)]+c d) 2sqrt2[tan^(-1)(sqrt 2t-1)+tan^(-1)(sqrt 2t+1)]+c