Under a fore `(10hati-3hatj+6hatk)` newton a bod of mass 5 kg moves from position `(6hati+5hatj-3hatk)` m to position `(10hati-2hatj+7hatk)`m. deduce the work done.

Under a force ( 10 hati - 3 hatj + 6 hatk) newton a body of mass 5 kg moves from position ( 6 hati + 5 hatj - 3 hatk) m to position ( 10 hati - 2hatj+ 7hatk) m . Deduce the work done.

Under a force of 10 hati - 3 hatj +6 hatk newton, a body of mass 5 kg is displaced from the position 6 hati + 5 hatj - 3 hatk to the position 10 hati - 2hatj + 7 hatk . Calculate the work done.

A force of (10hati-3hatj+6hatk)N acts on a body of 5 kg and displaces it from (6hati+5hatj-3hatk)m "to" (10hati-2hatj+7hatk)m . The work done is

If vecF = 3hati + 4hatj+5hatk and vecS=6hati +2hatj+5hatk , the find the work done.