If `log_(x+1)(2x-1)+log_(2x-1)(x+1)=2`, find x.

log_(2)(x+1)-log_(2)(3x-1)=2

log_(x-1)x*log_(x-2)(x-1)*...*log_(x-12)(x-11) = 2 ,x is equal to

log_(x-1)x*log_(x-2)(x-1)*...*log_(x-12)(x-11) = 2 ,x is equal to

log_(2)(x^(2)-1)=log_((1)/(2))(x-1)

If (log_(2)(4x^(2)-x-1))/(log_(2)(x^(2)+1))>1, then x may be

If log_(2) 6 + (1)/(2x ) =log_(2) (2^(1//x) + 8) , then the values of x are

2log x-log(x+1)-log(x-1)=

If log_(2)(x^(2)+1)+log_(13)(x^(2)+1)=log_(2)(x^(2)+1)log_(13)(x^(2)+1)*(x!=0) then log_(7)(x^(2)+24) is equal to

If log_(2) (9^(x - 1) + 7) - log_(2) (3^(x-1) + 1) = 2 , then values of x are

If log_(2)(3^(2x-2)+7)=2+log_(2)(3^(x-1)+1) then x=