[Find by vector method the horizontal force and the force inclined at an angle of `60^@` to the vertical whose resultant is a vertical force P.]

A force of 4N is inclined at an angle of 60^(@) from the vertical. Find out its components along horizontal and vertical directions.

A force of 4N is inclined at an angle of 60^(@) from the vertical. Find out its components along horizontal and vertical directions.

A force of 4N is inclined at an angle of 60^(@) from the vertical. Find out its components along horizontal and vertical directions.

A force of 4N is inclined at an angle of 60^(@) from the vertical. Find out its components along horizontal and vertical directions.

A block of mass m lying on a rough horizontal plance is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The block will remain in equilibrium, if the coefficient of friction between it and the surface is

A block of mass m lying on a rough horizontal plance is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The block will remain in equilibrium, if the coefficient of friction between it and the surface is

A block of mass m lying on a rough horizontal plance is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The block will remain in equilibrium, if the coefficient of friction between it and the surface is

A block of mass m lying on a horizontal plane , is acted upon by a horizontal force p and another force Q inclined at an angle theta to the vertical .The block will remain in equilibrium if the coefficient of friction between it and the surface is (assume p gt Q)