Suppose n is a positive integer such that `(n^2+48)` is a perfect square. what is n?

Suppose n is a positive integer such that (n^2 + 48) is a perfect square. What is the number of such n? (n<5)

When n is a positive integer,then (n^(2))! is

If n is a positive integer then .^(n)P_(n) =

The number of positive integers n such that n+9,16n+9,27n+9 are all perfect squares is

If n is a positive integer, then n^(3)+2n is divisible

The least value of the positive integers n such that (n+20)+(n+21)+(n+22)+...+(n+100) is a perfect square is.

If n is a positive integer, then ((n+4)!)/((n+7)!)=