If `tan theta=1` then `(8sin theta +5 cos theta)/(sin^3theta-2cos^3theta+7cos theta)=`

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

If 4tan theta=3, evaluate (4sin theta-cos theta+1)/(sin theta+cos theta-1)

Prove that : (1-sin theta cos theta)/ (cos theta (sec theta - cosec theta)) times (sin^2 theta - cos^2 theta)/(sin^3 theta + cos^3 theta) = sin theta

If 5 tan theta = 4 , show that ( 5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta) = (1)/(7)

If 5 tan theta = 4 , show that ( 5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta) = (1)/(7)

Prove that : (sin theta + sin 3theta + sin 5theta)/(cos theta + cos 3theta + cos 5theta) = tan 3theta

If tan theta=4 then ((tan theta)/((sin^(3)theta)/(cos theta)+sin theta cos theta)) is equal to

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

(sin theta-2sin^(3)theta)/(2cos^(3)theta-cos theta)=tan theta