The point from which the tangents to the circles `x^2 +y^2-8x + 40 = 0,5x^2+5y^2 -25x +80=0,`and `x^2 +y^2-8x + 16y + 160 = 0` are equal in length, is

The point from which the tangents to the circles: x^2+y^2-8x+40=0, 5x^2+5y^2-25x+80=0, x^2+y^2-8x+16y+160=0 are equal in length is :

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (51/5, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (17/16, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

If the lengths of tangents drawn to the circles x^(2) + y^(2) - 8x + 40 = 0 5x^(2) + 5y^(2) - 25x + 80 = 0 x^(2) + y^(2) - 8x + 16y + 160 = 0 From the point P are equal, then P is equal to

The number of common tangent to the circles x^(2) + y^(2) + 4x - 6y - 12 = 0 and x^(2) + y^(2) - 8x + 10y + 5 = 0 is

From a point P , tangents drawn to the circle x^2 + y^2 + x-3=0, 3x^2 + 3y^2 - 5x+3y=0 and 4x^2 + 4y^2 + 8x+7y+9=0 are of equal lengths. Find the equation of the circle through P , which touches the line x+y=5 at the point (6, -1) .

From a point P , tangents drawn to the circle x^2 + y^2 + x-3=0, 3x^2 + 3y^2 - 5x+3y=0 and 4x^2 + 4y^2 + 8x+7y+9=0 are of equal lengths. Find the equation of the circle through P , which touches the line x+y=5 at the point (6, -1) .

The equation (s) of common tangents (s) to the two circles x^(2) + y^(2) + 4x - 2y + 4 = 0 and x^(2) + y^(2) + 8x - 6y + 24 = 0 is/are