If `(7/3)^(-5)xx(7/3)^(-11)=(7/3)^(8n)` then `n=`

(3^7-:3^(-11))*(5^(8)-5^(-11))

Find n if : a. ((4)/(49))^(5)xx((4)/(49))^(n-3)=((2)/(7))^(16) b. ((5)/(7))^(12)xx[((7)/(5))^(2)]^(8)=((7)/(5))^(2n-6) c. ((9)/(25))^(4)xx((9)/(25))^(n)=((3)/(5))^(12) d. ((3)/(5))^(20)xx[((5)/(3))^(3)]^(6)=((3)/(5))^(3n-13)

(m+2)/(n+3)=(3)/(5) and (m+7)/(n+11)=(2)/(3) then solve m=?

3(7)/(11)+7(3)/(11)xx1(1)/(2)=?

(1)/(3)xx(5)/(7)xx(5)/(11) "of" ?=325

Find n if : a. (3^(4))^(5)=(3^(2))^(n) b. 5^(12)=125^(n) c. 7^(2n+4)xx7^(4)=(7^(8))^(2) d. 8^(6)=64^(n)

If n=2^(3)xx3^(4)xx5^(4)xx7, then the number of consecutive zeros in n, where n is a natural number,is ( a) 2( b ) 3 (c) 4 (d) 7

Simplify : a. [(3^(3))xx3^(4)]-:3^(4) b. 18^(6)-:3^(12) c. [(5^(6))^(9)xx(5^(15))^(5)]-[(5^(13))^(5)xx(5^(4))^(16)] d. (3^(5)xx10^(5)xx25)-:(5^(7)xx6^(5)) e. ((2)/(b))^(18)xxb^(12)xx(3^(4))^(3) f. [(2^(4))^(2)xx2^(12)]-:4^(2) g. 12^(8)-:3^(6) h. [(7^(7))^(8)xx(7^(9))^(5)]-[(7^(11))^(6)xx(7^(7))^(5)] i. (25^(2)xxp^(4)xxq^(8))-:(5^(3)xxp^(4)xxq^(7)) j. ((a)/(3))^(24)xx2^(8)xx(3^(6))^(4)

(2)/(11)times((-3)/(7))=((-3)/(7))times...