" Q6.Solve "ax+by=a-b" and "bx-ay=a+b

Solve: ax+by=a-b,quad bx-ay=a+b

Solve: ax+by=c,quad bx+ay=1+c

Solve: ax + by = a - b bx - ay = a + b

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab , then

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab, then

A,B,C,D are the points of intersection with the coordinate axes of the line ax+by=ab and bx+ay=ab. Then

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab, then

Solve: ax - by = 1 bx + ay = 0