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If f^(prime)(x^2)=(lnx)/(x^2)andf(1)=-1/...

If `f^(prime)(x^2)=(lnx)/(x^2)andf(1)=-1/4,t h e n(A)f(e)=0(B)f^(prime)(e)=1/20`

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f'(x^(2))=(ln x)/(x^(2)) and f(1)=-(1)/(4), then (A)f(e)=0(B)f'(e)=(1)/(20)

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