If `A sub B,` then `P(A nn B^c)=`

If A sub B, then (A'nn B')=?

If A sub B then P(A)sub P(B)

For all sets A, B and C, if A sub B , then A nn C sub B nn C .

For all sets A, B and C, if A sub B , then A nn C sub B nn C .

Prove that (i) A nn B sube A( ii) A nn B sube B( iii) If C sube A and C subebar(B), then C sube A nn B( iv )A=B rArr A nn C=B nn C for any set C, (v) If B sube A, then A nn B=B and conversely.

If P(A) = 0.7, P(B) = 0.4, P(A nn B) = 0.3, then P(A nn B') =

If P(A) = 0.7, P(B) = 0.4, P(A nn B) = 0.3, then P(A nn B') =

If A sub B and A sup C then A nn B nn C= "_______" .

Let P(E) denote the probability of occurrence of event E. If A and B are two events associated with an experiment such that |[P(A)-1,P(B),-P(A nn B)],[P(B),-P(A nn B),P(A)-1],[-P(A nn B),P(A)-1,P(B)]|=0 then (A) P(A uu B)=1 (B) P(A/B)=(P(A)+P(B)-1)/(P(B)) (C) if A sub B then P(B)=P(A uu B) (D) if A sub B then P(A)=1

Assertion (A) : If A sub B and B sub A then P(A) = P(B) Reason (R) : If A sub B then P (bar(A)) le P (bar (B))