[" ii) If "tan20^(0)=lambda" then show that "],[(tan160^(@)-tan110^(@))/(1+tan160^(@)tan110^(@))=(1-lambda^(2))/(2 lambda)]

If tan20^(@) = lambda then show that (tan 160^(@) -tan 110^(@))/(1+tan160^(@).tan110^(@)) = (1-lambda^2)/(2lambda) .

If tan20=lambda ,prove that (tan160^(@)-tan110^(@))/(1+tan160^(@)*tan110^(@))=(1-lambda^(2))/(2 lambda) .

(i) If tan 20^(@) = lambda then show that (tan 610^(@) + tan 700^(@))/(tan 560^(@) - tan 470^(@))=(1-lambda^(2))/(1+lambda^(2))

If tan 20^(@) =lamda, then (tan 160^(@) -tan 110^(@))/(1+ (tan 160^(@)) (tan 110^(@)))=

If tan 40^(@) = lambda , then (tan 140^(@) - tan 130^(@))/(1 + tan 140^(@) tan 130^(@)) =

If tan 40^(@)= lambda , then (tan 140^(@)-tan 130^(@))/(1+ tan 140^(@) tan 130^(@))=

If tan20^@=lamda , then (tan160^@-tan110^@)/(1+(tan160^@)(tan110^@))=

If tan 20^(@) =lamda, then (tan 160^(@) -tan 110^(@))/(1+ (tan 160^(@)) (tan 110^(@)))= ............. A) (1+ lamda ^(2))/(2 lamda) B) (1+ lamda^(2))/( lamda) C) (1- lamda^(2))/(lamda) D) (1- lamda^(2))/(lamda)