6x^(2)+kx-sqrt(6)=0;x=-(sqrt(3))/(2)

6x^(2)-sqrt(2)x-2=0

ln Delta ABC cosA= -(2)/(3) the equation with roots sin A ,tan A is 1) 6x^(2)+sqrt(5)x-5=0 2) 6x^(2)-sqrt(5)x+5=0 3) 6x^(2)-sqrt(5)x-5=0 4) 6x^(2)+sqrt(5)x+5=0

x^2+3sqrt(3)x+6

int(x+3sqrt(x^(2))+6sqrt(x))/(x(1+3sqrt(x)))dx

If the area of the triangle formed by the lines x=0,y=0,3x+4y-a(a>0) is 1, then a=(A)sqrt(6)(B)2sqrt(6)(C)4sqrt(6)(D)6sqrt(2)

If sqrt(2) is a zero of p(x)=6x^(3)+sqrt(2)x^(2)-10x-4sqrt(2), find the remaining zeros

Solve (i) x^(2) -(3sqrt2-2i)x-6sqrt2i=0

6sqrt(3)x^(2)-47x+5sqrt(3)

(6) sqrt(5)x^(2)-2sqrt(2)x-2sqrt(5)=0