In a reaction `PCI_(5)hArrPCI_(3) + CI_(2)` degree of dissociation is `30%` . If initial moles of `PCI_(3)` is one then total moles at equilibrium is

For the reaction PCI_(5)(g) rightarrow PCI_(3)(g) + CI_(2)(g)

The reaction, PCI_(5)hArrPCI_(3)+CI_(2) is started in a five litre container by taking one mole of PCI_(5) . If 0.3 mol PCI_(5) is there at equilibrium, concentration of PCI_(3) "and" K_(c) will respectively be:

For PCI_5(g) hArr PCI_3(g) +CI_2(g) , write the expression of K_c .

For PCI_5(g) hArr PCI_3(g) +CI_2(g) , write the expression of K_c .

A_(3)(g)hArr 3A(g) , In the above reaction, the initial conc. Of A_(3) is 'a' moles/lit. If x is degree of dissociation of A_(3) . The total number of moles at equilibrium will be

A_(3)(g)hArr 3A(g) , In the above reaction, the initial conc. Of A_(3) is 'a' moles/lit. If x is degree of dissociation of A_(3) . The total number of moles at equilibrium will be

For the reaction: PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g) The forward reaction at constant temperature is favoured by

A quantity of PCI _5 was heated in a 2 litre vessel at 525 K . It dissociates as PCI_5 (g) hArr PCI _3 (g) + CI_2 (g) At equilibrium 0.2 mol each of PCI_5 , PCl_3and Cl_2 is found in the reaction mixture. The equilibrium constant K_c for the reaction is -

A quantity of PCI _5 was heated in a 2 litre vessel at 525 K . It dissociates as PCI_5 (g) hArr PCI _3 (g) + CI_2 (g) At equilibrium 0.2 mol each of PCI_5 , PCl_3and Cl_2 is found in the reaction mixture. The equilibrium constant K_c for the reaction is -