If `cos alpha=(2 cos beta-1)/(2-cos beta),0 lt alpha,beta lt pi`, then `tan(alpha/2)/tan(beta/2)=`

cos alpha=(2cos beta-1)/(2-cos beta)(0

If cos alpha=(2cos beta-1)/(2-cos beta) then tan((alpha)/(2))*cot((beta)/(2)) has the equal to [where alpha,beta in(0,pi)]

If cos theta = ( cos alpha - cos beta )/(1- cos alpha cos beta ) " then " tan^(2)""((theta )/(2)) tan^(2)""((beta)/(2))=

If cos(alpha+beta)=3/5, sin(alpha-beta)=5/13 , and 0 lt alpha, beta lt pi/4 , then tan(2alpha) is equal to:

Given that cos ((alpha -beta)/(2)) = 2 cos ((alpha+ beta)/(2)), then tan ""(alpha)/(2) tan ""(beta)/(2) is equal to

Prove that cos^(-1)[(cos alpha +cos beta)/(1+cos alpha cos beta)]=2tan^(-1)("tan"(alpha)/(2)"tan"(beta)/(2))

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these