[" If "sec A=(17)/(8)" prove that "],[qquad (3-4*sin^(2)A)/(4cos^(2)A-3)=(3-tan^(2)pi)/(1+3tan^(2)A)]

If sec A=(17)/(8), verify that (3-4sin^(2)A)/(4cos^(2)A-3)=(3-tan^(2)A)/(1-3tan^(2)A)

If sec A=(5)/(4), verify that (3sin A-4sin^(3)A)/(4cos^(3)A-3cos A)=(3tan A-tan^(3)A)/(1-3tan^(2)A)

If secA=(17)/8 , verify that (3-4sin^2A)/(4cos^2A-3)=(3-tan^2A)/(1-3tan^2A)

If costheta=(8)/(17) ,verify that (3-4sin^(2)theta)/(4cos^(2)theta-3)=(3-tan^(2)theta)/(1-3tan^(2)theta) .

If costheta=(8)/(17) ,verify that (3-4sin^(2)theta)/(4cos^(2)theta-3)=(3-tan^(2)theta)/(1-3tan^(2)theta) .

Prove that: (sin^(2)pi)/(6)+(cos^(2)pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

" 1.Prove that : "sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

Prove that : sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))=-(1)/(2)

Prove that "sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)=(-1)/(2)

sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)