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In Fig . (QR)/(QS) = (QT)/(PR)and |ul(1...

In Fig . `(QR)/(QS) = (QT)/(PR)and` `|__ul(1)=|__ul(2)` . Show that `Delta PQS ~ Delta TQR`

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The correct Answer is:
`:. Delta PQS ~ Delta TQR ` (SAS postulate).
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