[f(x),=(e^(1/x)-1)/(e^(1/x)+1)" for "x!=0],[,=1quad " for "x=0]}" at "x=0

If f(x)={:{((e^(1/x)-1)/(e^(1/x)+1)", for " x !=0),(1", for " x=0):} , then f is

If f(x)=(e^(1//x)-1)/(e^(1//x)+1)" for "x ne 0, f(0)=0" then at x=0, f(x) is"

Discuss the continulity of f(x) = (e^(1/x) -1)/(e^(1/x) + 1) , x ne 0 and f(0) = 0 at x = 0 .

Examine the continuity of the following function at the indicated pionts. f(x)={{:(,(e^(1/x)-1)/(e^(1/x)+1), x ne 0),(,0, x =0):}" at x=0"

The function f(x)={(e^(1/x)-1)/(e^(1/x)+1),x!=0 \ \ \ \ \ \ \ 0,x=0 at x=0

Discuss the continuity of f ( x ) = (e^(1)/(x)-1)/(e^(1)/(x)+1), x ne 0 and f(0) = 0 at x=0

The function f(x) =(e^(1//x^(2))/(e^(1//x^(2))-1)" for "x ne 0,f(0)=1" at x =0 is"

If f(x) is continuous at x=0 , where f(x){:{((1)/(1+e^(1/x))", for " x!=0),(k", for " x=0):} , then k=