A hot liquid kept in a beaker cools from `80^(@)C` to `70^(@)C` in two minutes. If the surrounding temperature is `30^(@)C`, find the time of coolilng of the same liquid from `60^(@)C` to `50^(@)C`.

A liquid cools from 70^(@) C to 60^(@) C in 5 minutes. If the temperautre of the surrounding is 30^(@) C, what is the time taken by the liquid to cool from 50^(@) C to 40^(@) C ?

A liquid contained in a beaker cools from 80^(@)C to 60^(@)C in 10 minutes. If the temperature of the surrounding is 30^(@)C , find the time it will take to cool further to 48^(@)C . Here cooling take place ac cording to Newton's law of cooling.

A liquid cools from 70^@C to 60^@C in 5 minutes. If the temperature of the surrounding is constant at 30^@C , then the time taken by the liquid to cool from 60^@C to 50^@C is

A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

A cup of tea cools from 80^(@)C to 60^(@)C in one minute. The ambient temperature is 30^(@)C . In cooling from 60^(@)C to 50^(@)C it will take

A cup of tea cools from 80^(@)C to 60^(@)C in one minute. The ambient temperature is 30^(@)C . In cooling from 60^(@)C to 50^(@)C it will take

A cup of tea cools from 80^(@)C to 60^(@)C in one minute. The ambient temperature is 30^(@)C . In cooling from 60^(@)C to 50^(@)C it will take