The dimensions of `K` in the equation `W=1/2Kx^(2)` is

Find out the dimension of K in the equation, W= (1)/(2) Kx^(2) . Here x and W are the elongation and the potential energy respectively of a spring.

The dimensions of k in equation F = kx are

The dimensions of k in equation F = kx are

The dimensions of k in equation F = kx are

Find the dimensions of V in the equation y= A sin omega((x)/(V)-k)

The dimension of omega in the expression y= Asin (omegat-kx) is

The equation k^(2)x^(2)+kx+1=0 has

If the product of the roots of the equation x^(2)-3kx+2e^(2log k)-1=0 is 17 then k=