The specific conductivity of a saturated solution of silver chloride is `2.30 xx 10^(-6) m ho cm^(-1) " at " 25^(@)C`. Calculate the solubility of silver chloride at `25^(@)C " if " lamda_(Ag^(+)) = 61.9 m ho cm^(2) mol^(-1) and lamda_(Cl^(-)) = 76.3 m ho cm^(2) mol^(-1)`

The solubility product of silver chloride is 1 xx 10^(-10)" at 25"^@C. Calculate the solubility of silver chloride in 0.1 M sodium chloride.

The specific conductance of a saturated solution of AgCl in water is 1.826xx10^(-6)"ohm"^(-1)cm^(-1) at 25^(@)C . Calculate its solubility in water at 25^(@)C . [Given Lambda_(m)^(oo)(Ag^(+))=61.92" ohm"^(-1)cm^(2)mol^(-1) "and" Lambda_(m)^(oo)(Cl^(-))=76.34" ohm"^(-1)cm^(2)mol^(-1)] .

At 298 K, The specific conductivity of a saturated solution of silver chloride in water is 2.30xx10^(-5)Scm^(-1) . Calculate its solubility in gL^(-1) at 298 K. Given lambda_(m)^(@)(Ag^(+))" and "lambda_(m)^(@)(Cl^(-)) are 61.9 and 76.3 S cm^(2)mol^(-1) respectively.

The conductivity of a saturated solution of AgCl at 25^(@)C after subtracting the conductivity of water is 2.28 xx 10^(-6) S cm^(-1) . Calculate the solubility product of AgCl at 25^(@)C if Lambda_(m)^(0) (AgCl) 138.3 S cm^(2) mol^(-1)

The specific conductivity of the saturated aqueous solution of AgCl is 1.82xx10^(-6) ohm^(-1) cm^(-1) at 298K. Calculate me solubility of AgCl. [wedge_(m)^(@)(Ag^(+))=61.83 ohm^(-1) cm^(2) mol^(-1)] and wedge_(m)^(@) (CI)^(-)=76.41 ohm^(-1) cm^(2) mol^(-1)

The specific conductance of a saturated solution of AgCl at 25^@C is 1.821xx10^(-5) mho cm^(-1) . What is the solubility of AgCl in water (in g L^(-1) ) , if limiting molar conductivity of AgCl is 130.26 mho cm^(2) mol^(-1) ?

The specific conductance of a saturated solution of AgCl at 25^@C is 1.821xx10^(-5) mho cm^(-1) . What is the solubility of AgCl in water (in g L^(-1) ) , if limiting molar conductivity of AgCl is 130.26 mho cm^(2) mol^(-1) ?