A block of mass `1 kg` moving with a speed of `4 ms^(-1)`, collides with another block of mass `2 kg` which is at rest. The lighter block comes to rest after collision. The loss in `KE` of the system is

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body is

Choose the correct options A block of mass m moving at a speed of u collides with another block of mass 2 m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is

A block of mass m moving with speed v collides with another block of mass 2m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is

A block of mass m moving at speed upsilon collides with another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

A block of mass m moving at speed upsilon collides with another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

A block of mass m moving at a speed v collides with another block of mass 2 m at rest.The lighter block comes to rest after the collision.Find the coefficient of restitution.

A block of mass m moving at speed upsilon collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.