`tan5 0^(@)-2tan1 0^(@)=`

If cot 20^@=p then (tan16 0^(@)-tan11 0^(@))/(1+tan16 0^(@)tan11 0^(@))=

(tan8 0^(@)-tan1 0^(@))/tan70^(@)

S o l v e(sin1 0^(@))^(tanx+tan3x)=tan1 5^(@)+tan3 0^(@)+tan1 5^(@)tan3 0^(@), x in (0,pi]

Evaluate : (2sin68^(0))/(cos22^(0))-(2cot15^(0))/(5tan75^(0))-(3tan45^(0)tan20^(@)tan40^(@)tan50^(@)tan70^(@))/(5)

tan(100^(@))+tan(125^(@))+tan(100^(@))tan(125^(@))= ............ A) 0 B) 1/2 C) -1 D) 1

(2tan3 0^(@))/(1-tan^2 3 0^(@))

(2tan3 0^(@))/(1-tan^2 3 0^(@))

If tan25^(0)=a, then the value of (tan205^(@)-tan115^(0))/(tan245^(0)+tan335^(@)) in terms of 'a' is

The value of (tan7 0^0-tan2 0^0)/(tan5 0^0)=

tan181^(0)tan182^(@)tan183^(@)dots tan267^(0)tan268^(@)tan269^(@)=1