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[" Momentum "rho=4t^(2)," then force act...

[" Momentum "rho=4t^(2)," then force acting at "],[t=2s" is "]

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A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where, q = 4m s^(-2) , p - 3m s^(-1) and r = 5m s^(-3) . The force acting on the body at t = 2s is

The velocity of a body of mass 2 kg as a function of t is given by v(t) = 2t hati + t^(2)hatj . Find the momentum and the force acting on it, at time t = 2s.

The velocity of a body of mass 2 kg as a function of t is given by vec v (t) = 2t hat i + t^2 hatj . Find the momentum and the force acting on it, at time t = 2s.

Kinetic energy of a particle moving in a straight line varies with time t as K = 4t^(2) . The force acting on the particle

Kinetic energy of a particle moving in a straight line varies with time t as K = 4t^(2) . The force acting on the particle

The momenta of a body in two perpendicular directions at any time 't' are given by P_(x)=2t^(2) +6 and P_(y)=(3t^(2))/(2)+3 . The force acting on the body at t =2 sec is .

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The momentum of a body in two perpendicular direction at any time 't' are given by P_(x) =2t^(2) + 6 and P_(y) = (3t^(2))/2 + 3 . The force acting on the body at t= 2 sec is