Consider the numbers `4^n`, where n is a natural number. Cheek whether there is any value of n for which `4^n`ends with the digit zero.

Explanation

To determine whether there is any value of \( n \) for which \( 4^n \) ends with the digit zero, we can follow these steps:

### Step 1: Understanding the condition for a number to end with zero
A number ends with the digit zero if it is divisible by 10. Since \( 10 = 2 \times 5 \), a number must be divisible by both 2 and 5 to end with zero.

### Step 2: Analyze \( 4^n \)
We can express \( 4^n \) in terms of its prime factors:
\[
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