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3tan^-1(1/2)+2tan^-1(1/5)+sin^-1(142/(65...

`3tan^-1(1/2)+2tan^-1(1/5)+sin^-1(142/(65sqrt(5)))`

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To simplify, `3*tan^-1(1/2) + 2*tan^-1(1/5) + sin^-1(142/(66*sqrt5))` Consider, `sin^-1(142/(66*sqrt5))`, from its general triangle: `P = 142` `H = 66*sqrt5` `B = sqrt(P^2 + H^2)` `B = 31` `:. sin^-1(142/(66*sqrt5)) = tan^-1(142/31)` We have, ...
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