In the figure the variation of compenent...

In the figure the variation of compenents of acceleration of a particle of mass is `1 kg` is shown w.r.t. time. The initial velocity of the particle is `vec u=(- 3i + 4j) m//s`. The totak work done by the resultant force on the particle in time from `t = 0` to `t = 4` seconds is :
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In the figure the variation of components of acceleration of a particle of mass is 1 kg is shown w.r.t. time. The initial velocity of the particle is vec u=(- 3i + 4j) m//s . The total work done by the resultant force on the particle in time from t = 0 to t = 4 seconds is : .

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In the figure the variation of compenents of acceleration of a particle of mass is `1 kg` is shown w.r.t. time. The initial velocity of the particle is `vec u=(- 3i + 4j) m//s`. The totak work done by the resultant force on the particle in time from `t = 0` to `t = 4` seconds is : .

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In the figure the variation of compenents of acceleration of a particle of mass is `1 kg` is shown w.r.t. time. The initial velocity of the particle is `vec u=(- 3i + 4j) m//s`. The totak work done by the resultant force on the particle in time from `t = 0` to `t = 4` seconds is :
.