To find the distance `d` over which a signal can be seen clearly in foggy conditions, a railways-engineer uses dimensions and assumes that the distance depends on the mass density `rho` of the fog, intensity (power/area) `S` of the light from the signal and its frequency `f`. the engineer finds that `d` is proportional to `S^(1//n)`. the value of `n` is

To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density rho of the fog, intensity ("power"//"area") S of the light from the signal and its frequency f. The engineer finds that d is proportional to S^(1//n) . The value of n is.

To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density rho of the fog, intensity ("power"//"area") S of the light from the signal and its frequency f. The engineer finds that d is proportional to S^(1//n) . The value of n is.

A satellite S_(1) of mass m is revolving at a distance of R from centre of earth and the other satellite S_(2) of mass 4m is revolving at a distance of 4R from the centre of earth. The time periods of revolution of two satellites are in the raito 1 : n. Find the value of n.

The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)) . (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' .

Two slits S_(1) and S_(2) on the x-axis and symmetric with respect to y-axis are illuminated by a parallel monochromatic light beam of wavelength lamda . The distance between the slits is d(gt gt lamda) . Point M is the mid point of the line S_(1)S_(2) and this point is considered as the origin. The slits are in horizontal plane. The interference pattern is observed on a horizontal palte (acting as screen) of mass M , Which is attached to one end of a vertical spring of spring constant K. The other end of the spring is fixed to ground At t=0 the plate is at a distance D(gt gt d) below the plane of slits and the spring is in its natural length. The plate is left from rest from its initial position. Find the x ad y co-ordinates of the n^(th) maxima on the plate as a function of time. Asuume that spring is light andplate always remains horizontal.

[" A solid sphere of radius "R" is charged with "],[" volume charge density "rho=Kr^(n)," where "K" and "n],[" are constants and "r" is the distance from its "],[" centre.If electric field inside the sphere at "],[" distance "r" is proportional to "r^(4)," then find the "],[" value of "n.]

In a young’s double slit experiment the distance between slits S1 and S2 is d and distance of slit plane from the screen is D (gtgt d) . The point source of light (S) is placed a distance (d) / (2 ) below the principal axis in the focal plane of the convex lens (L). The slits S1 and S2 are located symmetrically with respect to the principal axis of the lens. Focal length of the lens is f (gtgt d) . Find the distance of the central maxima of the fringe pattern from the centre (O) of the screen.

Monochromatic light of wavelength lamda passes through a very narrow slit S and then strikes a screen placed at a distance D = 1m in which there are two parallel slits S_(1) and S_(2) as shown. Slit S_(1) is directly in line with S while S_(2) is displaced a distance d to one side. The light is detected at point P on a second screen, equidistant from S_(1) and S_(2) When either slit S_(1) or S_(2) is open equal light intensities I are measured at point P. When both slits are open, the intensity is three times as large i.e. 3 I . If the minimum possible wavelength is Nd^(2) , then find the value of N (d lt lt D)